4[t-2]-3[t+1]=

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Solution for 4[t-2]-3[t+1]= equation: 


Simplifying
4[t + -2] + -3[t + 1] = 0

Reorder the terms:
4[-2 + t] + -3[t + 1] = 0
[-2 * 4 + t * 4] + -3[t + 1] = 0
[-8 + 4t] + -3[t + 1] = 0

Reorder the terms:
-8 + 4t + -3[1 + t] = 0
-8 + 4t + [1 * -3 + t * -3] = 0
-8 + 4t + [-3 + -3t] = 0

Reorder the terms:
-8 + -3 + 4t + -3t = 0

Combine like terms: -8 + -3 = -11
-11 + 4t + -3t = 0

Combine like terms: 4t + -3t = 1t
-11 + 1t = 0

Solving
-11 + 1t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 1t = 0 + 11

Combine like terms: -11 + 11 = 0
0 + 1t = 0 + 11
1t = 0 + 11

Combine like terms: 0 + 11 = 11
1t = 11

Divide each side by '1'.
t = 11

Simplifying
t = 11

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